Program to show arithmetic Operators, Implicit/Explicit Type casting

#include<stdio.h>
#include<conio.h>

int main()
  {
  int a=9,b=2;
  float c;

  int i1;
  int i2;

  float f1;
  float f2;

  clrscr();

  i1=9/2;    //integer divided by integer
  printf("\n1--> %d",i1);      //Answer=4

  printf("\n2--> %d",9/2);       //Answer=4

  i2=9.0/2;    //implicit typecasting
  printf("\n3--> %d",i2);        //Answer=4

  printf("\n4--> %d",9.0/2);    //Answer=0//Mismatch

  f1=9.0/2;
  printf("\n5--> %d",f1);    //Answer=0//Mismatch

  f2=9/2;    //integer divided by integer//implicit typecasting
  printf("\n6--> %d",f2);       //Answer=0//Mismatch

  i1=9/2;    //integer divided by integer
  printf("\n7--> %f",i1);    //Answer=0.000000//Mismatch

  printf("\n8--> %f",9/2);    //Answer=0.000000//Mismatch

  i2=9.0/2;    //implicit typecasting
  printf("\n9--> %f",i2);    //Answer=0.000000//Mismatch

  f2=9/2;    //integer divided by integer//implicit typecasting
  printf("\n10--> %f",f2);    //Answer=4.000000

  printf("\n11--> %f",9.0/2);    //Answer=4.500000

  printf("\n12--> %d",9.0+2.0);    //Answer=0//Mismatch

  printf("\n13-> %f",9.0-2.0);    //Answer=7.000000
  printf("\n14--> %d",9*2);     //Answer=18

  printf("\n15--> %d",-14%3);    //Answer=-2
  printf("\n16--> %d",-14%-3);    //Answer=-2
  printf("\n17--> %d",14%-3);    //Answer=2

  c=a/b;    //integer divided by integer//implicit typecasting
  printf("\n18--> %f",c);    //Answer=4.000000

  c=(float)a/b;        //Explicit Typecasting
  printf("\n19--> %f",c);    //Answer=4.500000
  getch();
  return 0;
  }